Recommanded Free YOUTUBE Lecture: High Avalibility Application On AWS Cloud
  1. get_jumin_info
  2. 주민등록번호에서 정보를 파싱하는 간단한 예제입니다.
  3. [멍]
  4. Version 0.1
  5. 2004/01/28

설명

1900년대에 태어난 사람들에 대한 주민정보를 가져오는 예제입니다.

그러나 2000년도 이상 태어난 사람은 나이 계산하는 코드에서 에러를 발생시킬수 있습니다.

이 부분에 대한 처리를 어떻게 하고 있는지 궁금하네요

아시는 분은 코드를 버전업해주세요 ^^;

사용방법

get_jumin_info.c

사용법: ./get_jumin_info 741121-1XXXXXX

#include <stdio.h>
#include <string.h>
#include <time.h>
int main(int argc, char **argv)
{
char sex;
char birth[10];
int age;
if (argc != 2)
{
printf("Usage: get_jumin_info <>\n");
printf("\t) 741121-1XXXXXX\n");
return 1;
}
get_jumin_info(argv[1], &sex, &age, birth);
printf(" = %s\n", argv[1]);
switch (sex)
{
case '1':
printf(": \n");
break;
case '2':
printf(": \n");
break;
}
printf(" = %s\n", birth);
printf(" = %d\n", age);
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

코드

void get_jumin_info(char *jumin, char *sex, int *age, char *birth)
{
time_t t;
struct tm *tptr;
char birthday[5];
*sex = jumin[7];
memcpy(birth, jumin, 6);
birth[6] = '\0';
sprintf(birthday, "19%c%c", jumin[0], jumin[1]);
t = time(NULL);
tptr = localtime(&t);
*age = 1900 + tptr->tm_year - atoi(birthday); // 2000 !!
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

변경사항

2004/01/28